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86 lines
2.5 KiB
86 lines
2.5 KiB
/*
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* MinIO Cloud Storage, (C) 2019 MinIO, Inc.
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*
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* Licensed under the Apache License, Version 2.0 (the "License");
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* you may not use this file except in compliance with the License.
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* You may obtain a copy of the License at
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*
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* http://www.apache.org/licenses/LICENSE-2.0
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*
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* Unless required by applicable law or agreed to in writing, software
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* distributed under the License is distributed on an "AS IS" BASIS,
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* WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
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* See the License for the specific language governing permissions and
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* limitations under the License.
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*/
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package lifecycle
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import (
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"encoding/xml"
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"errors"
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"io"
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"strings"
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)
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var (
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errLifecycleTooManyRules = errors.New("Lifecycle configuration allows a maximum of 1000 rules")
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errLifecycleNoRule = errors.New("Lifecycle configuration should have at least one rule")
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errLifecycleOverlappingPrefix = errors.New("Lifecycle configuration has rules with overlapping prefix")
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)
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// Lifecycle - Configuration for bucket lifecycle.
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type Lifecycle struct {
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XMLName xml.Name `xml:"LifecycleConfiguration"`
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Rules []Rule `xml:"Rule"`
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}
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// IsEmpty - returns whether policy is empty or not.
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func (lc Lifecycle) IsEmpty() bool {
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return len(lc.Rules) == 0
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}
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// ParseLifecycleConfig - parses data in given reader to Lifecycle.
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func ParseLifecycleConfig(reader io.Reader) (*Lifecycle, error) {
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var lc Lifecycle
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if err := xml.NewDecoder(reader).Decode(&lc); err != nil {
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return nil, err
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}
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if err := lc.Validate(); err != nil {
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return nil, err
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}
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return &lc, nil
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}
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// Validate - validates the lifecycle configuration
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func (lc Lifecycle) Validate() error {
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// Lifecycle config can't have more than 1000 rules
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if len(lc.Rules) > 1000 {
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return errLifecycleTooManyRules
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}
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// Lifecycle config should have at least one rule
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if len(lc.Rules) == 0 {
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return errLifecycleNoRule
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}
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// Validate all the rules in the lifecycle config
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for _, r := range lc.Rules {
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if err := r.Validate(); err != nil {
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return err
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}
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}
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// Compare every rule's prefix with every other rule's prefix
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for i := range lc.Rules {
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if i == len(lc.Rules)-1 {
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break
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}
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// N B Empty prefixes overlap with all prefixes
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otherRules := lc.Rules[i+1:]
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for _, otherRule := range otherRules {
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if strings.HasPrefix(lc.Rules[i].Filter.Prefix, otherRule.Filter.Prefix) ||
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strings.HasPrefix(otherRule.Filter.Prefix, lc.Rules[i].Filter.Prefix) {
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return errLifecycleOverlappingPrefix
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}
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}
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}
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return nil
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}
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